UVA 10042 Smith Numbers

不停地比較. 錯的就加一, 直到找到答案. 只要算sum of factor的那一部份正確就過了.

uva10042.cpp
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#include <cstdio>
#include <cmath>

int sum_of_digit(int v) {
int sum = 0;
while(v > 0) {
sum += v%10;
v /= 10;
}
return sum;
}

int sum_of_factor(int v) {
if(v == 0) return 0;
if(v == 1) return 2;

int sum = 0;
int remain = v;

int limit = sqrt(v) + 1;
int count = 0;

while(remain % 2 == 0) {
remain /= 2;
sum += 2;
count++;
}

for(int i = 3; i <= limit; i += 2) {
while(remain % i == 0) {
remain /= i;
sum += sum_of_digit(i);
count++;
}
}

if(count == 1 || (count > 1 && remain != 1)) sum += sum_of_digit(remain);
if(count == 0) sum += 1 + sum_of_digit(v);
return sum;
}

int main() {
int ncase,v;
scanf("%d", &ncase);

for(;ncase > 0; --ncase) {
scanf("%d", &v);
int vv = v + 1;
while(sum_of_digit(vv) != sum_of_factor(vv))
vv++;
printf("%d\n", vv);
}

return 0;
}